(2y^2+3y-4)/(y-2)

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Solution for (2y^2+3y-4)/(y-2) equation: 


D( y )

y-2 = 0

y-2 = 0

y-2 = 0

y-2 = 0 // + 2

y = 2

y in (-oo:2) U (2:+oo)

(2*y^2+3*y-4)/(y-2) = 0

2*y^2+3*y-4 = 0

2*y^2+3*y-4 = 0

DELTA = 3^2-(-4*2*4)

DELTA = 41

DELTA > 0

y = (41^(1/2)-3)/(2*2) or y = (-41^(1/2)-3)/(2*2)

y = (41^(1/2)-3)/4 or y = (-(41^(1/2)+3))/4

(y+(41^(1/2)+3)/4)*(y-((41^(1/2)-3)/4)) = 0

((y+(41^(1/2)+3)/4)*(y-((41^(1/2)-3)/4)))/(y-2) = 0

( y+(41^(1/2)+3)/4 )

y+(41^(1/2)+3)/4 = 0 // - (41^(1/2)+3)/4

y = -((41^(1/2)+3)/4)

( y-((41^(1/2)-3)/4) )

y-((41^(1/2)-3)/4) = 0 // + (41^(1/2)-3)/4

y = (41^(1/2)-3)/4

y in { -((41^(1/2)+3)/4), (41^(1/2)-3)/4 }

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